A) \[3.61\times {{10}^{10}}\]
B) \[31.1\times {{10}^{15}}\]
C) \[3.6\times {{10}^{12}}\]
D) \[3.11\times {{10}^{15}}\]
Correct Answer: A
Solution :
\[\frac{dN}{dt}=\lambda N\] \[\lambda =\frac{0.6931}{{{t}_{1/2}}}=\frac{0.6931}{1620\times 365\times 60\times 60}\] \[N=\frac{6.023\times {{10}^{23}}}{226}\] \[\frac{dN}{dt}=\frac{0.6931\times 6.023\times {{10}^{23}}}{1620\times 365\times 24\times 60\times 60\times 226}=3.61\times {{10}^{10}}\]
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