Manipal Medical Manipal Medical Solved Paper-2015

  • question_answer
    A body from height h is dropped, if the coefficient of restitution is e, then calculate the height achieved after one bounce.

    A) \[{{h}_{1}}={{e}^{4}}h\]                                  

    B) \[h=e\,{{h}_{1}}\]

    C) \[{{h}_{1}}=h{{e}^{2}}\]                  

    D) \[h={{h}_{1}}/e\]

    Correct Answer: C

    Solution :

    When a body falls from height h, it strikes the ground with a velocity\[v=\sqrt{2gh}\]. Let it rebounced with a velocity v and rise to a weight \[{{h}_{1}}\]. \[v=\sqrt{2g{{h}_{1}}}\] \[e=\frac{v}{u}\sqrt{\frac{{{h}_{1}}}{h}}\]                  Clearly, \[{{h}_{1}}={{e}^{2}}h\]


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