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Manipal Medical Manipal Medical Solved Paper-2015

  • question_answer
    The ionisation energy of the electron in the   hydrogen atom in its ground state is 13.6 eV.  The atoms are excited to higher energy levels   to emit radiations of 6 wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between

    A) \[n=3\,to\,n=\]1 states 

    B) \[n=4\,to\,n=\]3 states

    C) \[n=3\,to\,n=\]2 states

    D) \[n=2\,to\,n=\]1 states

    Correct Answer: B

    Solution :

    Number of wavelengths\[=\frac{n(n-1)}{2}\]where, n = number of orbit from which transition takes place. \[\therefore \]     \[6=\frac{n(n-1)}{2}\] \[n=4\] \[\therefore \]The wavelength of emitted radiations will be maximum for transition n = 4 to n = 3.


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