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Manipal Medical Manipal Medical Solved Paper-2015

  • question_answer
    A person near point of vision is 100 cm. Then, the power of lens he must wear so as to have normal vision is

    A) -3 D                                          

    B) + 3 D  

    C) -1 D                                          

    D) +1 D

    Correct Answer: B

    Solution :

    \[f=\frac{yD}{y-D}=\frac{100\times 25}{100-25}=\frac{100}{3}cm=\frac{1}{3}m\] \[P=\frac{1}{f}=+3\,D\]


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