A) \[[ML{{T}^{-3}}]\] and \[[ML{{T}^{-4}}]\]
B) \[[ML{{T}^{-3}}]\] and \[[M{{L}^{2}}{{T}^{-4}}]\]
C) \[[ML{{T}^{-4}}]\] and \[[ML{{T}^{1}}]\]
D) \[[ML{{T}^{-3}}]\] and \[[M{{L}^{2}}{{T}^{-4}}]\] From the principle of dimensional homogeneity \[[a]=\left[ \frac{F}{t} \right]=[ML{{T}^{-3}}]\] \[[b]=\left[ \frac{F}{{{t}^{2}}} \right]=[ML{{T}^{-4}}]\]
Correct Answer: A
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