A) 1/3
B) 1/2
C) 4/9
D) 9/5
Correct Answer: C
Solution :
Since, \[r=\frac{\sqrt{2mqV}}{qB}=\sqrt{\frac{2mV}{q{{B}^{2}}}}=\frac{{{r}_{1}}}{{{r}_{2}}}=\sqrt{\frac{{{m}_{1}}}{{{m}_{2}}}}\] \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{r_{1}^{2}}{r_{2}^{2}}\] Hence, \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{(2)}^{2}}}{{{(3)}^{2}}}=\frac{4}{9}\]You need to login to perform this action.
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