A) 1
B) \[\frac{m}{M}\]
C) \[\frac{M-m}{M+m}\]
D) \[\frac{m}{M+m}\]
Correct Answer: B
Solution :
As net horizontal force acting on the system is zero, hence, momentum must remain conserved. Hence \[mu+0=0+M{{v}_{2}}\] \[{{v}_{2}}=\frac{mu}{M}\] As per definition, \[e=\frac{({{v}_{2}}-{{v}_{1}})}{({{u}_{2}}-{{u}_{1}})}=\frac{{{v}_{2}}-0}{0-u}\] \[=\frac{{{v}_{2}}}{u}=\frac{M}{u}=\frac{m}{M}\]You need to login to perform this action.
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