A) \[\frac{mvit}{{{t}_{1}}}\]
B) \[\frac{m{{v}_{1}}t}{{{t}_{1}}}\]
C) \[\frac{m{{v}_{1}}{{t}^{2}}}{{{t}_{1}}}\]
D) \[\frac{mv_{1}^{2}t}{{{t}_{1}}^{2}}\]
Correct Answer: D
Solution :
From \[v=u+at\], \[v=0+a{{t}_{i}}\] \[F=ma=\frac{m{{v}_{1}}}{{{t}_{1}}}\] \[\left( \because a=\frac{{{v}_{1}}}{{{t}_{1}}} \right)\] Velocity acquired in t sec = at \[v=\frac{{{v}_{1}}}{{{t}_{1}}}t\] Power = F v \[=\left( \frac{m{{v}_{1}}}{{{t}_{1}}} \right)\left( \frac{{{v}_{1}}}{{{t}_{1}}}t \right)=\left( \frac{mv_{1}^{2}}{t_{1}^{2}} \right)t\]
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