A) 5.2g
B) 3.2 g
C) 4.6 g
D) 1.9g
Correct Answer: B
Solution :
\[{{w}_{B}}=1.5\times {{10}^{-3}}g\] \[{{m}_{B}}=19\times 12+21\times 1+14+3\times 16=311\] \[m=\frac{{{w}_{B}}/{{m}_{B}}}{{{M}_{A}}}\times 1000\] \[1.5\times {{10}^{-3}}=\frac{1.5\times {{10}^{-3}}/311}{{{M}_{A}}}\times 1000\] \[{{m}_{A}}=\frac{1.5\times {{10}^{-3}}}{311\times 1.5\times {{10}^{-3}}}\times 1000\] \[=\frac{1000}{311}=3.2g\]You need to login to perform this action.
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