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Manipal Medical Manipal Medical Solved Paper-2015

  • question_answer
    In an adsorption experiment, a graph between log \[\left( \frac{x}{m} \right)\] versus log p is found to be linear with slope of 45°. The intercept on log \[\left( \frac{x}{m} \right)\]axis was found to 0.3010. The amount of the gas adsorbed per gram of charcoal under the pressure of 0.5 atm will be

    A)  1.0                                           

    B) 2.0

    C) 0.50                                          

    D) 0.25

    Correct Answer: A

    Solution :

    \[\frac{x}{m}=k{{p}^{1/n}}\] Or, \[\log \frac{x}{m}=\log \,\,k+\frac{1}{n}\log \,p\] \[\therefore \] Plot of \[\log \frac{x}{m}\]vs. log p is linear With slope \[=\frac{1}{n}\] and intercept = log k Hence, \[\frac{1}{n}=\tan \theta =\tan {{45}^{\circ }}=1\,i.e.\,n=1\] and \[\log \,k=0.3010\]or                \[k=anti\log \,\,(0.3010)=2\] At \[p=0.5\,\,atm,\frac{x}{m}=k{{p}^{1/n}}=2\times {{(0.5)}^{1}}=1.0\]


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