A) Cl
B) \[C{{l}^{-}}\]
C) \[C{{l}_{2}}\]
D) \[{{F}^{-}}\]
Correct Answer: A
Solution :
\[CFC{{l}_{3}}\xrightarrow{hv}\overset{\bullet }{\mathop{Cl}}\,+\overset{\bullet }{\mathop{CFC{{l}_{2}}}}\,\] Hence, \[\overset{\bullet }{\mathop{Cl}}\,\]reacts with \[{{O}_{3}}\]through a chain reaction as follows: \[\overset{\bullet }{\mathop{Cl}}\,\,+\,{{O}_{3}}\to Cl{{O}^{\bullet }}+{{O}_{2}}\] \[\overset{\bullet }{\mathop{Cl}}\,\,+\,O\to C{{l}^{\bullet }}+{{O}_{2}}\]
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