A) \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}\]
B) \[C{{H}_{3}}C{{H}_{2}}OS{{O}_{3}}H\]
C) \[C{{H}_{2}}=C{{H}_{2}}\]
D) \[C{{H}_{3}}C{{H}_{2}}OH\]
Correct Answer: D
Solution :
\[\begin{align} & {{C}_{2}}{{H}_{5}}OH\xrightarrow{PB{{r}_{3}}}\underset{(A)}{\mathop{{{C}_{2}}{{H}_{5}}Br}}\,\xrightarrow{Alc.\,KOH}\underset{(B)}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\, \\ & \mathop{\downarrow }_{{{H}_{2}}O/{{H}_{2}}S{{o}_{4}}} \\ & \underset{(C)}{\mathop{C{{H}_{3}}C{{H}_{2}}OC}}\, \\ \end{align}\]
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