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Manipal Medical Manipal Medical Solved Paper-2015

  • question_answer
    Which one/ones of the following reactions will yield 2-propanol? (I) \[C{{H}_{3}}-CHO\xrightarrow[(ii){{H}_{2}}O]{(i)C{{H}_{3}}Mgl}\] (II) \[C{{H}_{2}}O\xrightarrow[(ii){{H}_{2}}O]{(i){{C}_{2}}{{H}_{5}}Mgl}\] (III) \[C{{H}_{2}}=CH-C{{H}_{3}}+{{H}_{2}}O\xrightarrow{{{H}^{+}}}\] (IV) \[C{{H}_{2}}=CH-C{{H}_{3}}\xrightarrow{Neutral\,\,KMn{{O}_{4}}}\]

    A) I and III

    B) II and III

    C) III and IV                

    D) II and IV

    Correct Answer: A

    Solution :

    \[I.\,C{{H}_{3}}CHO\xrightarrow[(ii)\,{{H}_{2}}O]{(i)\,C{{H}_{3}}Mgl}\]\[\begin{align}   & OH \\  & | \\  & C{{H}_{3}}-CH-C{{H}_{3}} \\ \end{align}\] \[II.\,C{{H}_{2}}O\xrightarrow[(ii)\,{{h}_{2}}O]{(i){{C}_{2}}{{H}_{5}}Mgl}{{C}_{2}}{{H}_{5}}C{{H}_{2}}OH\] \[III.\,\,C{{H}_{3}}CH=C{{H}_{2}}+{{H}_{2}}O\xrightarrow{{{H}^{+}}}\] \[\begin{align}   & H \\  & | \\  & C{{H}_{3}}-CH-C{{H}_{3}} \\ \end{align}\] \[\begin{align}   &  \\  & IV.\,C{{H}_{3}}CH=C{{H}_{2}}\xrightarrow[Neutral]{KMn{{O}_{4}}}C{{H}_{3}}CH-C{{H}_{2}} \\  & |\,\,| \\  & OH\,\,OH \\ \end{align}\]


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