A) \[\underset{\begin{smallmatrix} || \\ \text{O} \end{smallmatrix}}{\mathop{C}}\,H-C{{H}_{2}}C{{H}_{2}}\underset{\begin{smallmatrix} || \\ \text{O} \end{smallmatrix}}{\mathop{C}}\,-O\,Et\]
B) \[\begin{align} & C{{H}_{3}}-CH-COO\,Et \\ & | \\ & OH \\ \end{align}\]
C) \[C{{H}_{2}}=CH-COO\,Et\]
D) \[\begin{align} & C{{H}_{3}}-CH-COO\, \\ & | \\ & OH \\ \end{align}\]
Correct Answer: C
Solution :
\[{{C}_{2}}{{H}_{2}}=\underset{(A)}{\mathop{CH}}\,-CH\xrightarrow{{{H}^{+}}/{{H}_{2}}O}C{{H}_{2}}=CH-COOH\] \[\xrightarrow{Etoh/{{H}^{+}}}C{{H}_{2}}=\underset{B}{\mathop{CH}}\,-COO\,Et\]
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