A) \[{{(C{{H}_{3}})}_{2}}C=CH-C{{H}_{2}}COOH\]
B) \[{{(C{{H}_{3}})}_{2}}C=CH-CO-COOH\]
C) \[{{(C{{H}_{3}})}_{2}}C=CH-COOH\]
D) \[{{(C{{H}_{3}})}_{2}}CH-COOH\]
Correct Answer: C
Solution :
\[\begin{align} & C{{H}_{3}}\,\,O \\ & |\,\,\,|| \\ & C{{H}_{3}}-C=CH-C-C{{H}_{3}} \\ & C{{H}_{3}} \\ & | \\ & \xrightarrow{NaOH+l\,2}C{{H}_{3}}-C=CH-COONa+CH{{I}_{3}} \\ \end{align}\]Mesityl oxide can be prepared by aldol condensation of acetone
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