question_answer

\[C{{O}_{2}}+P\to \,Q\xrightarrow{{{P}_{2}}{{O}_{5}}}R\] Which of the following are P and S in the above series of reactions?

A) \[{{C}_{2}}{{H}_{5}}MgX\]and \[{{({{C}_{2}}{{H}_{5}})}_{2}}NC{{H}_{3}}\]

B) \[C{{H}_{3}}MgX\] and N-methyl -2 ? butanamine

C) \[C{{H}_{3}}MgX\] and N-ethyl ? 2 butanamine

D) \[{{C}_{2}}{{H}_{5}}MgX\]and \[{{(C{{H}_{3}})}_{2}}N{{C}_{2}}{{H}_{5}}\]

Correct Answer: C

Solution :

\[C{{O}_{2}}+\underset{(P)}{\mathop{C{{H}_{3}}MgX}}\,\xrightarrow{{{H}_{2}}O}\underset{(Q)}{\mathop{C{{H}_{3}}COOH}}\,\xrightarrow[-{{H}_{2}}O]{{{P}_{2}}{{O}_{5}}}\]\[\begin{align}   & NH-{{C}_{2}}{{H}_{5}} \\  & | \\  & \underset{(R)}{\mathop{{{(C{{H}_{3}}CO)}_{2}}}}\,O\xrightarrow[(S)]{C{{H}_{3}}-CH-{{C}_{2}}{{H}_{5}}} \\ \end{align}\]