A) \[\frac{2}{3}\]mole of \[MnO_{4}^{-}\] and \[\frac{1}{3}\] mole of \[Mn{{O}_{2}}\]
B) \[\frac{1}{3}\] mole of \[MnO_{4}^{-}\] and \[\frac{2}{3}\] mole of \[Mn{{O}_{2}}\]
C) \[\frac{1}{2}\]mole of \[M{{n}_{2}}{{O}_{7}}\] and \[\frac{1}{3}\] mole of \[Mn{{O}_{2}}\]
D) \[\frac{2}{3}\] mole of \[M{{n}_{2}}{{O}_{7}}\] and \[\frac{1}{3}\]mole of \[Mn{{O}_{2}}\]
Correct Answer: A
Solution :
\[M{{n}^{6+}}\to M{{n}^{7+}}+1{{e}^{-}}\] \[M{{n}^{6+}}+2{{e}^{-}}\to M{{n}^{4+}}\] \[\therefore \] \[3MnO_{4}^{2-}\to 2MnO_{4}^{-}+Mn{{O}_{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
