A) H
B) H2
C) 2H
D) \[\sqrt{2}H\]
Correct Answer: D
Solution :
Given: \[H=V\] ...(1) where,\[H=\]horizontal component of magnetic field \[V=\]vertical component of magnetic field Therefore, resultant intensity \[I=\sqrt{{{H}^{2}}+{{V}^{2}}}\] \[I=\sqrt{{{H}^{2}}+{{H}^{2}}}\] \[I=\sqrt{2{{H}^{2}}}\] \[I=\sqrt{2}H\]You need to login to perform this action.
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