A) \[\frac{1}{200}\] cm
B) 2 cm
C) 200 cm
D) 100 cm
Correct Answer: C
Solution :
Magnification of astronomical telescope \[m=\frac{{{f}_{0}}}{20}\]where\[{{f}_{o}}=\]focal length of objective lens \[{{f}_{e}}=\]focal length of eye piece \[\therefore \] \[10=\frac{{{f}_{o}}}{20}\] \[\Rightarrow \] \[{{f}_{o}}=10\times 20\] \[\Rightarrow \] \[{{f}_{o}}=200\,cm\]You need to login to perform this action.
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