A) 0.025
B) 0.04
C) 0.02
D) 0.05
Correct Answer: B
Solution :
\[\underset{a}{\mathop{PC{{l}_{5}}}}\,\underset{0}{\mathop{PC{{l}_{3}}}}\,+\underset{0}{\mathop{C{{l}_{2}}}}\,\] In equil, \[(a-x)=0.1\text{ }mol.\,\,\,\,\,\,\text{ }0.2\text{ }mol.\text{ }\,\,\,\,\,\,\,\,0.2\text{ }mol.\] Hence, \[{{K}_{c}}=\frac{[PC{{l}_{3}}][C{{l}_{2}}]}{[PC{{l}_{5}}]}=\frac{\left( \frac{0.2}{10} \right)\times \left( \frac{0.2}{10} \right)}{\left( \frac{0.1}{10} \right)}\]\[=0.04\]You need to login to perform this action.
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