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MGIMS WARDHA MGIMS WARDHA Solved Paper-2003

  • question_answer
    A small current carrying loop acts as a small magnet. The area of the loop is A and magnetic moment is M. The current in the loop will be :

    A) \[\frac{A}{M}\]                                

    B) \[\frac{M}{A}\]

    C) \[MA\]                                

    D) \[{{A}^{2}}M\]

    Correct Answer: B

    Solution :

    For magnetic dipole, \[M=IA\]where,\[M=\]magnetic moment of the magnet \[J=\]current flowing in the loop \[A=\]area of current carrying loop \[\therefore \]  \[I=\frac{M}{A}\]


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