A) \[{{\sin }^{-1}}\left( \frac{1}{2} \right)\]
B) \[{{\sin }^{-1}}\left( \frac{9}{8} \right)\]
C) \[{{\sin }^{-1}}\left( \frac{9}{8} \right)\]
D) \[{{\sin }^{-1}}\left( \frac{5}{7} \right)\]
Correct Answer: C
Solution :
From the relation, \[\frac{1}{\sin C}{{=}_{\omega }}{{\mu }_{g}}\] Or \[\frac{1}{\sin C}=\frac{{{\mu }_{g}}}{{{\mu }_{\omega }}}\] where\[C=\]critical angle \[{{\mu }_{g}}=\]refractive index of glass\[=\frac{3}{2}\] \[{{\mu }_{\omega }}=\]refractive index of water\[=\frac{4}{3}\] \[\therefore \] \[\sin C=\frac{{{\mu }_{\omega }}}{{{\mu }_{g}}}\] \[\sin C=\frac{4/3}{3/2}\] \[\sin C=\frac{8}{9}\] Hence, \[C={{\sin }^{-1}}\left( \frac{8}{9} \right)\]You need to login to perform this action.
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