A) 15 Hz
B) 30 Hz
C) 45 Hz
D) 60 Hz
Correct Answer: A
Solution :
Fundamental frequency in an organ pipe opened at both ends. \[{{n}_{1}}=\frac{\upsilon }{2l}\]and fundamental frequency in an organ pipe closed at one end \[{{n}_{2}}=\frac{\upsilon }{4l}\] \[\therefore \] \[\frac{{{n}_{2}}}{{{n}_{1}}}=\frac{\upsilon /41}{4/2l}=\frac{1}{2}\] \[{{n}_{2}}=\frac{{{n}_{1}}}{2}\] \[{{n}_{2}}=\frac{30}{2}\] \[{{n}_{2}}=15Hz\]You need to login to perform this action.
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