A) \[+19{}^\circ \]
B) \[+112{}^\circ \]
C) \[+52{}^\circ \]
D) \[+100{}^\circ \]
Correct Answer: C
Solution :
The specific rotation of \[\text{ }\!\!\alpha\!\!\text{ -D-}\]glucose is\[+113{}^\circ \]and that of \[\text{ }\!\!\beta\!\!\text{ -D-}\]glucose is\[+19{}^\circ \]. The specific rotation of their mixture, in equilibrium, is\[+52{}^\circ \].You need to login to perform this action.
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