A) Neutron
B) \[\alpha -\]particle
C) Proton
D) Deuteron
Correct Answer: B
Solution :
\[\alpha -\]particle can be used to convert is\[_{13}A{{l}^{27}}\] into\[_{15}{{P}^{30}}\]. \[_{13}A{{l}^{27}}{{+}_{2}}H{{e}^{4}}{{\xrightarrow{{}}}_{15}}{{P}^{30}}{{+}_{0}}{{n}^{1}}\]You need to login to perform this action.
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