A) 1.2 A
B) 0.7A
C) 0.5 A
D) 0.3 A
Correct Answer: B
Solution :
The current flowing through the shunt is \[{{I}_{s}}=\frac{G}{S+G}I\] Where,\[S=\]shunt resistance \[=2\,\Omega \] \[G=\]galvanometer resistance \[=5\,\Omega \] \[I=1A\] \[\therefore \] \[{{I}_{s}}=\frac{5}{2+5}\times 1=\frac{5}{7}\] \[{{I}_{s}}=0.7\,A\]You need to login to perform this action.
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