A) oxidising property
B) acidic property
C) basic property
D) reducing property
Correct Answer: D
Solution :
\[S{{O}_{2}}\]act as bleaching agent due to its reducing property. \[S{{O}_{2}}+2H{{ & }_{2}}O\xrightarrow[{}]{{}}{{H}_{2}}S{{O}_{4}}+2H\]coloured matter\[+H\to \]colorless matter
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