A) 30.38 joule
B) 25 joule
C) 5 k joule
D) 16 joule
Correct Answer: A
Solution :
\[{{V}_{1}}=100mL\] \[{{V}_{2}}=250mL\] Pressure P = 2 atm or\[2\times 1.01\times {{10}^{5}}N{{m}^{-2}}\] Work done by the gas \[W=\Delta PV\]or \[P({{V}_{2}}-{{V}_{1}})\] Put the value in given formula \[W=2\times 1.01\times {{10}^{5}}(0.250\times {{10}^{-3}}-0.100\times {{10}^{-3}})\] \[=2\times 1.01\times {{10}^{5}}\times .15\times {{10}^{-3}}\] \[=30.38\text{ }joule\]
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