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MGIMS WARDHA MGIMS WARDHA Solved Paper-2004

  • question_answer
    Five particles of mass 2 kg are attached to the rim of a circular disc of radius m and negligible mass. Moment of inertia of the system about the axis passing through the centre of the disc and perpendicular to its plane is:

    A) 1 kgm2                                 

    B) 0.1 kg m2

    C) 2kgm2                                  

    D) 0.2kgm2

    Correct Answer: B

    Solution :

     The moment of inertia of the given system that contains 5 particles each of mass 2 kg on the rim of circular disc of radius 0.1 m and of negligible mass is given by = M.I. of disc + M.I. of particles Since the mass of the disc is negligible therefore, M.I. of the system = M.I. of particles \[=5\times 2\times {{(0.1)}^{2}}=0.1\,kg\,{{m}^{2}}\]


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