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MGIMS WARDHA MGIMS WARDHA Solved Paper-2004

  • question_answer
    A particle is executing the motion \[x=a\,\cos (\omega t-\theta ).\]The maximum velocity of the particle is :        

    A) \[a\,\omega \,\cos \theta \]                      

    B) \[a\,\omega \,\]

    C) \[a\,\omega \,\sin \theta \]                       

    D) none of these

    Correct Answer: B

    Solution :

    Given equation is \[x=a\cos (\omega t-\theta )\] So, velocity\[\left| \frac{dx}{dt} \right|=a\omega \sin (\omega t-\theta )\] At\[(\omega t-\theta )=90{}^\circ ,\]the velocity will be maximum, therefore the maximum velocity is\[\upsilon =a\omega \]


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