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MGIMS WARDHA MGIMS WARDHA Solved Paper-2004

  • question_answer
    A monoatomic gas supplied the heat \[Q\] very slowly keeping the pressure constant. The work done by the gas will be :

    A) \[\frac{2}{3}Q\]

    B)                        \[\frac{3}{5}Q\]

    C) \[\frac{2}{5}Q\]                               

    D) \[\frac{1}{5}Q\]

    Correct Answer: C

    Solution :

    For monoatomic gas at constant pressure \[\frac{\Delta U}{Q}=\frac{3}{5}\] Or           \[\Delta U=\frac{3Q}{5}\] Now,   applying   first   law   of thermodynamics \[\,W=\Delta Q-\Delta U\] \[=Q-\frac{3Q}{5}\] \[=\frac{2Q}{5}\]             


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