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MGIMS WARDHA MGIMS WARDHA Solved Paper-2004

  • question_answer
    A bar magnet of magnetic moment \[\mathbf{\vec{M}}\] is placed in the magnetic field \[\mathbf{\vec{B}}\] The Torque acting on the magnet is :

    A) \[\mathbf{\vec{M}\times \vec{B}}\]                                     

    B) \[\mathbf{\vec{M}\times \vec{B}}\]

    C) \[\frac{1}{2}\mathbf{\vec{M}\times \vec{B}}\]                                

    D) \[\mathbf{\vec{M}}+\mathbf{\vec{B}}\]

    Correct Answer: A

    Solution :

    Torque acting on the magnet is given by \[\overrightarrow{\tau }=\overrightarrow{M}\times \overrightarrow{B}\] Here:\[\overrightarrow{M}=\]magnetic moment, \[\overrightarrow{B}=\]magnetic field.


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