MGIMS WARDHA MGIMS WARDHA Solved Paper-2004

  • question_answer
    To make the frequency double of a spring oscillator, we have to :

    A) reduce the mass to one fourth

    B) quardruple the mass

    C) double the mass

    D) half the mass

    Correct Answer: A

    Solution :

    The frequency of spring oscillator is \[\upsilon =\frac{1}{2\pi }\sqrt{\frac{k}{m}}\] \[\Rightarrow \]               \[\upsilon \propto \sqrt{\frac{1}{m}}\] Hence,   \[\frac{{{\upsilon }_{1}}}{{{\upsilon }_{2}}}\propto \sqrt{\frac{{{m}_{2}}}{{{m}_{1}}}}\] Or           \[\frac{{{m}_{1}}}{{{m}_{2}}}={{\left( \frac{{{\upsilon }_{1}}}{{{\upsilon }_{2}}} \right)}^{2}}\]                 \[={{\left( \frac{{{\upsilon }_{1}}}{{{\upsilon }_{2}}} \right)}^{2}}=\frac{1}{4}\] \[{{m}_{2}}=\frac{{{m}_{1}}}{4}\]


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