MGIMS WARDHA MGIMS WARDHA Solved Paper-2004

  • question_answer
    A particle executing SHM has amplitude m and frequency 60 Hz. The maximum acceleration of particle is :

    A) \[60{{\pi }^{2}}\,m/{{s}^{2}}\]                                   

    B) \[80{{\pi }^{2}}\,m/{{s}^{2}}\]

    C) \[120{{\pi }^{2}}\,m/{{s}^{2}}\]                                 

    D) \[144{{\pi }^{2}}\,m/{{s}^{2}}\]

    Correct Answer: D

    Solution :

    Maximum acceleration of particle \[=a{{\omega }^{2}}=a{{(2\pi f)}^{2}}\] \[=4a{{\pi }^{2}}{{f}^{2}}\] \[=4\times 0.01\times {{\pi }^{2}}\times {{(60)}^{2}}\] \[=144{{\pi }^{2}}m/{{s}^{2}}\]


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