A) 1 kgm2
B) 0.1 kg m2
C) 2kgm2
D) 0.2kgm2
Correct Answer: B
Solution :
The moment of inertia of the given system that contains 5 particles each of mass 2 kg on the rim of circular disc of radius 0.1 m and of negligible mass is given by = M.I. of disc + M.I. of particles Since the mass of the disc is negligible therefore, M.I. of the system = M.I. of particles \[=5\times 2\times {{(0.1)}^{2}}=0.1\,kg\,{{m}^{2}}\]You need to login to perform this action.
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