MGIMS WARDHA MGIMS WARDHA Solved Paper-2004

  • question_answer
    A gas at state A changes to state B through path I and II shown in figure. The change in internal energy is \[\Delta {{U}_{1}}\] and \[\Delta {{U}_{2}}\] respectively. Then :

    A) \[\Delta {{U}_{1}}>\Delta {{U}_{2}}\]                     

    B) \[\Delta {{U}_{1}}<\Delta {{U}_{2}}\]

    C) \[\Delta {{U}_{1}}=\Delta {{U}_{2}}\]                     

    D) \[\Delta {{U}_{1}}=\Delta {{U}_{2}}=0\]

    Correct Answer: C

    Solution :

    Change in internal energy of the system does not depend on path followed. So,          \[\Delta {{U}_{1}}=\Delta {{U}_{2}}\]


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