A) the momentum changes by \[m\upsilon \]
B) the momentum changes by \[2m\upsilon \]
C) the kinetic energy changes by \[(1/2)\,m{{\upsilon }^{2}}\]
D) the kinetic energy changes by\[\,m{{\upsilon }^{2}}\]
Correct Answer: B
Solution :
Initial velocity \[{{\upsilon }_{1}}=\upsilon \] Final velocity \[{{\upsilon }_{2}}=-\upsilon \] Initial momentum\[{{p}_{1}}=m\upsilon \] Final momentum \[{{p}_{2}}=m(-\upsilon )=-m\upsilon \] Change in momentum \[\Delta p={{p}_{1}}-{{p}_{2}}\] \[=m\upsilon -(-m\upsilon )\] \[=2m\upsilon \]You need to login to perform this action.
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