MGIMS WARDHA MGIMS WARDHA Solved Paper-2004

  • question_answer
    The solubility of\[S{{b}_{2}}{{S}_{3}}\]in water is \[1.0\times {{10}^{-5}}\]mol/litre at 298 K. What will be its solubility product?

    A)  \[108\times {{10}^{-25}}\]                          

    B) \[1.0\times {{10}^{-25}}\]

    C)  \[144\times {{10}^{-25}}\]                          

    D) \[126\times {{10}^{-24}}\]

    Correct Answer: B

    Solution :

                     \[\underset{s\,mol/lilt}{\mathop{S{{b}_{2}}{{S}_{3}}}}\,\underset{2s}{\mathop{2S{{b}^{3+}}}}\,+\underset{3s}{\mathop{3{{S}^{2-}}}}\,\] Solubility product                 \[({{K}_{sp}})={{[S{{b}^{3+}}]}^{2}}{{[{{S}^{2-}}]}^{3}}\]                 \[={{(2s)}^{2}}{{(3s)}^{3}}\] \[=108\text{ }{{s}^{5}}\] \[=109\times {{(1.0\times {{10}^{-5}})}^{5}}\] \[=108\times {{10}^{-25}}\]


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