A) \[HCHO\]
B) \[C{{H}_{3}}CHO\]
C) \[C{{H}_{3}}COC{{H}_{3}}\]
D) \[{{C}_{2}}{{H}_{5}}OH\]
Correct Answer: A
Solution :
lodoform test is given by those compounds which have\[-C{{H}_{3}}CO\]group or on oxidation yields this group. Formaldehyde does not have\[-C{{H}_{3}}CO\]group, hence it does not give iodoform test. \[C{{H}_{3}}CHO+\xrightarrow{{{I}_{2}}/NaOH}\underset{yellow\text{ }ppt}{\mathop{CH{{I}_{3}}\downarrow }}\,\]
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