A) \[FeS{{O}_{4}}.\text{ }NO\]
B) \[[Fe{{(S{{O}_{4}})}_{2}}.\text{ }NO]{{H}_{2}}O\]
C) \[F{{C}_{2}}{{(S{{O}_{4}})}_{3}}.NO\]
D) none of these
Correct Answer: A
Solution :
Brown ring in the ring-test of\[NO_{3}^{-}\]is formed due to the formation of\[FeS{{O}_{4}}.NO\]. NO at the junction of two liquids.
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