MGIMS WARDHA MGIMS WARDHA Solved Paper-2004

  • question_answer
    A coil having N turns carries a current as shown in the figure. The magnetic field intensity at point P is :

    A) \[\frac{{{\mu }_{0}}Ni{{R}^{2}}}{2({{R}^{2}}+{{x}^{2}})3/2}\]       

    B) \[\frac{{{\mu }_{0}}Ni}{2R}\]

    C) \[\frac{{{\mu }_{0}}Ni{{R}^{2}}}{{{(R+x)}^{2}}}\]                               

    D)  zero

    Correct Answer: A

    Solution :

     From the formula, magnetic field intensity at point P, shown in given figure in a coil carrying current\[i\]and having N turns is given by \[B=\frac{{{\mu }_{0}}Ni{{R}^{2}}}{2{{({{R}^{2}}+{{x}^{2}})}^{3/2}}}\]


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