A) 1.0 V
B) 0.5 V
C) 0.2 V
D) 0.1 V
Correct Answer: D
Solution :
Potential of big drop \[V={{n}^{2/3}}V'\] \[V'=\]potential of small drop \[n=\]no. of drops =125 \[V=2.5\] \[\therefore \] \[2.5={{(125)}^{2/3}}V'\] \[2.5=25V'\] \[V'=\text{ }0.1\text{ }volt\]You need to login to perform this action.
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