A) isocyanide
B) cyanide
C) phenol
D) salicylic acid
Correct Answer: A
Solution :
Aniline reacts with\[CHC{{l}_{3}}\]and\[KOH\]as\[KOH\]Follows \[\underset{Aniline}{\mathop{{{C}_{6}}{{H}_{5}}N{{H}_{2}}}}\,+CHC{{l}_{3}}+3KOH\,alc\xrightarrow{\Delta }\] \[\underset{Phenyl\,isocyanide}{\mathop{{{C}_{6}}{{H}_{5}}N\overset{\to }{\mathop{=}}\,C}}\,+3KCl+3{{H}_{2}}O\]You need to login to perform this action.
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