A) Zinc with cold and dilute\[HN{{O}_{3}}\]
B) Zinc with concentrated\[HN{{O}_{3}}\]
C) Copper with cold and dilute\[HN{{O}_{3}}\]
D) Heating\[N{{H}_{4}}N{{O}_{3}}\]
Correct Answer: A
Solution :
NO (Nitric oxide) is synthesized in lab by copper with cold and dilute\[HN{{O}_{3}}\]. \[3Cu+\underset{Dil.}{\mathop{8HN{{O}_{3}}}}\,\xrightarrow{{}}3Cu{{(N{{O}_{3}})}_{2}}+\underset{\begin{smallmatrix} Nitric \\ oxide \end{smallmatrix}}{\mathop{2NO}}\,\] \[+3{{H}_{2}}O\] By reacting\[Zn\]with cold and dil. \[HN{{O}_{3}},N{{H}_{4}}N{{O}_{3}}\]is formed. \[4Zn\underset{Dil.\text{ }and\text{ }cold}{\mathop{+10HN{{O}_{3}}}}\,\xrightarrow{{}}4Zn{{(N{{O}_{3}})}_{2}}+3{{H}_{2}}O\] \[+N{{H}_{4}}N{{O}_{3}}+2N{{O}_{2}}\] By reacting\[Zn\]with cone. nitric acid\[N{{O}_{2}}\]is formed By heating\[N{{H}_{4}}N{{O}_{3}},\]nitrous oxide is formed. \[N{{H}_{4}}N{{O}_{3}}\xrightarrow{{}}\underset{\begin{smallmatrix} Nitrous \\ \,\,\,oxide \end{smallmatrix}}{\mathop{{{N}_{2}}O}}\,+2{{H}_{2}}O\]
You need to login to perform this action.
You will be redirected in
3 sec
