A) 1
B) 2
C) 3
D) 4
Correct Answer: A
Solution :
Magnetic moment of\[{{K}_{3}}[Fe{{(CN)}_{6}}]=1.7\text{ }BM\]Magnetic moment \[=\sqrt{n(n+2)}\]n= number of unpaired electrons present in molecule\[1.7=n\sqrt{(n+2)}\]n2 + 2n - 2.89 = 0 then n = 0.97 or 1You need to login to perform this action.
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