MGIMS WARDHA MGIMS WARDHA Solved Paper-2005

  • question_answer
    If the critical angle for total internal reflection from medium to vacuum is 30°, the velocity of light in medium is :

    A) \[3\times {{10}^{8}}m/s\]                           

    B) \[1.5\times {{10}^{8}}m/s\]

    C) \[6\times {{10}^{8}}m/s\]                           

    D) \[\sqrt{3}\times {{10}^{8}}m/s\]

    Correct Answer: B

    Solution :

    Refactive index of medium \[\mu =\frac{1}{\sin C}=\frac{1}{\sin 30}\]                 \[=\frac{1}{1/2}\] \[\therefore \]Velocity of light in the medium                 \[\upsilon =\frac{c}{\mu }\]                 \[=\frac{3\times {{10}^{8}}}{2}=1.5\times {{10}^{8}}m/s\]


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