A) \[\mu ={{r}_{p}}\times {{g}_{m}}\]
B) \[{{r}_{p}}=\mu \times {{g}_{m}}\]
C) \[{{g}_{m}}=\mu \times {{r}_{p}}\]
D) none of these
Correct Answer: A
Solution :
We know \[\mu ={{\left( \frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}} \right)}_{{{i}_{p}}=cons\tan t}}\] \[{{r}_{p}}={{\left( \frac{\Delta {{V}_{p}}}{\Delta {{i}_{p}}} \right)}_{{{i}_{p}}=cons\tan t}}\] \[{{g}_{m}}={{\left( \frac{\Delta {{i}_{p}}}{\Delta {{V}_{g}}} \right)}_{{{V}_{p}}=cons\tan t}}\] \[\therefore \] \[\mu =\frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}}=\frac{\Delta {{V}_{g}}}{\Delta {{i}_{p}}}\times \frac{\Delta {{i}_{p}}}{\Delta {{V}_{g}}}\] \[\Rightarrow \] \[\mu ={{r}_{p}}\times {{g}_{m}}\]
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