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MGIMS WARDHA MGIMS WARDHA Solved Paper-2005

  • question_answer
    An electron and a proton are possessing same   amount of kinetic energies. The de-Broglie wavelength is greater for :

    A) electron                              

    B) proton

    C) both same                         

    D) none of these

    Correct Answer: A

    Solution :

    de-Broglie wavelength \[\lambda =\frac{h}{\sqrt{2m{{E}_{k}}}}\] Where h = Planck's constant Elutron and proton have same kinetic energy, So,          \[\lambda \propto \frac{1}{m}\]               Mass of electron is less than that of Proton, so electron will have greater wavelength.


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