A) \[\frac{1}{\sqrt{2}}\]
B) \[1-\frac{1}{\sqrt{2}}\]
C) \[20%\]
D) \[\frac{1}{8}\]
Correct Answer: B
Solution :
\[T=2\,days,\,{{t}_{1/2}}=4\,days\] \[\frac{N}{{{N}_{o}}}={{\left( \frac{1}{2} \right)}^{\frac{T}{{{t}_{1/2}}}}}={{\left( \frac{1}{2} \right)}^{\frac{2}{4}}}=\frac{1}{\sqrt{2}}\] \[\therefore \] \[N={{N}_{o}}.\frac{1}{\sqrt{2}}\] Hence, amount of substance decayed in 2 days will be \[={{N}_{o}}-{{N}_{O}}.\frac{1}{\sqrt{2}}=1-\frac{1}{\sqrt{2}}\]
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