A) \[C{{H}_{3}}COCl\xrightarrow{LiAl{{H}_{4}}}\]
B) \[{{C}_{2}}{{H}_{5}}CHO\xrightarrow[{{H}^{+}}/{{H}_{2}}O]{C{{H}_{3}}MgBr}\]
C) \[{{(C{{H}_{3}})}_{2}}CH{{C}_{2}}{{H}_{5}}\xrightarrow{Cu}\]
D)
Correct Answer: B
Solution :
Propionaldehyde give chiral molecule on reaction with Grignard reagent In resulting product C* is an asymmetric carbon atom as all the four valencies are satisfied with four different atoms or groups.
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